Government Autonomous College, Rourkela
CGPA to percentage
Quick answer: At Government Autonomous College, Rourkela, a CGPA of 8 is about 75.0%, using the formula % = (CGPA − 0.5) × 10. Last checked 2026-08-21.
Government Autonomous College, Rourkela — CGPA → %
How Government Autonomous College, Rourkela converts CGPA to percentage
Government Autonomous College, Rourkela (Odisha) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8. Applying the Government Autonomous College, Rourkela formula % = (CGPA − 0.5) × 10 gives a percentage of about 75.0%.
Source & verification
‘Model Regulation for Under Graduate Programme’, effective 2019-20 onwards (statewide Utkal-affiliated template).
College contact
Address: At/P.O. - Panposh (Rourkela), Dist - Sundargarh, Odisha - 769004, India
Email: principalgacr@gmail.com (per Sundargarh district portal)
Phone: 0661-3502418 (Helpline) / 06612664586
Website: www.gacrkl.ac.in
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