Government Autonomous College, Rourkela
percentage to CGPA
Quick answer: At Government Autonomous College, Rourkela, 75.0% is about a CGPA of 8, reversing the formula % = (CGPA − 0.5) × 10. Last checked 2026-08-21.
Government Autonomous College, Rourkela — % → CGPA
How to reverse Government Autonomous College, Rourkela's CGPA formula
Government Autonomous College, Rourkela (Odisha) converts CGPA to percentage using % = (CGPA − 0.5) × 10. This page inverts that formula.
Worked example
Take a percentage of 75.0%. Reversing the Government Autonomous College, Rourkela formula % = (CGPA − 0.5) × 10 gives a CGPA of about 8.
Source & verification
‘Model Regulation for Under Graduate Programme’, effective 2019-20 onwards (statewide Utkal-affiliated template).
College contact
Address: At/P.O. - Panposh (Rourkela), Dist - Sundargarh, Odisha - 769004, India
Email: principalgacr@gmail.com (per Sundargarh district portal)
Phone: 0661-3502418 (Helpline) / 06612664586
Website: www.gacrkl.ac.in
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