Shri Ram Murti Smarak College of Engineering & Technology (SRMS CET), Bareilly
CGPA to percentage
Quick answer: At Shri Ram Murti Smarak College of Engineering & Technology (SRMS CET), Bareilly, a CGPA of 8.2 is about 82%, using the official formula % = CGPA × 10. (official source)
Shri Ram Murti Smarak College of Engineering & Technology (SRMS CET), Bareilly — CGPA → %
How Shri Ram Murti Smarak College of Engineering & Technology (SRMS CET), Bareilly converts CGPA to percentage
Shri Ram Murti Smarak College of Engineering & Technology (SRMS CET), Bareilly (Uttar Pradesh) uses the formula % = CGPA × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8.2 on the 10-point scale. Applying the official Shri Ram Murti Smarak College of Engineering & Technology (SRMS CET), Bareilly formula % = CGPA × 10 gives a percentage of about 82%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
SRMS College of Engineering & Technology, Bareilly — M.Tech Ordinance (CBCS, effective 2018-19), Clause 15
Formula from SRMS CET's own M.Tech Ordinance (CBCS, 2018-19, Clause 15): Percentage = CGPA × 10, manually verified. The college is affiliated to Dr. A.P.J. Abdul Kalam Technical University (AKTU). AKTU's B.Tech Ordinance (2018-19) specifies (CGPA − 0.75) × 10, while its CBCS ordinance (Clause 15) specifies CGPA × 10 — use the conversion matching your program/ordinance.
College contact
Address: Ram Murti Puram, 13 KM Bareilly–Nainital Road, Bhojipura, Bareilly – 243202, Uttar Pradesh, India
Email: cet@srmscet.edu
Phone: 0581-2582246
Website: official contact page
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