Farook College (Autonomous), Kozhikode
CGPA to percentage
Quick answer: At Farook College (Autonomous), Kozhikode, a CGPA of 8 is about 80.0%, using the formula % ≈ CGPA × 10 (University of Calicut CBCSS convention). Last checked 2026-08-21.
Farook College (Autonomous), Kozhikode — CGPA → %
How Farook College (Autonomous), Kozhikode converts CGPA to percentage
Farook College (Autonomous), Kozhikode (Kerala) uses the formula % ≈ CGPA × 10 (University of Calicut CBCSS convention) to convert a 10-point CGPA into a percentage. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8. Applying the Farook College (Autonomous), Kozhikode formula % ≈ CGPA × 10 (University of Calicut CBCSS convention) gives a percentage of about 80.0%.
Source & verification
The college's own Office of the Controller of Examinations ‘Ten Point Indirect Grading System’ (UG 2019 Admission onwards) confirms the University of Calicut CBCSS grade bands (95+→O, 85-94→A+, 75-84→A, ...). The University of Calicut's widely-cited CBCSS convention for autonomous affiliated colleges (Farook College, Providence Women's, Devagiri, St. Joseph's) uses % ≈ CGPA × 10 as the standard conversion, though this is an indirect (band-based) grading system rather than a continuous linear one, so the identity is a convention, not a mathematical certainty.
College contact
Address: Farook College P.O., Kozhikode - 673632, Kerala, India
Email: mail@farookcollege.ac.in
Phone: 0495-2440660 / 0495-2440661 / 9562977811
Website: farookcollege.ac.in
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