Indian Institute of Technology Roorkee (IIT Roorkee)
CGPA to percentage
Quick answer: At Indian Institute of Technology Roorkee (IIT Roorkee), a CGPA of 8.5 is about 85%, using the official formula % = CGPA × 10. (official source)
Indian Institute of Technology Roorkee (IIT Roorkee) — CGPA → %
How Indian Institute of Technology Roorkee (IIT Roorkee) converts CGPA to percentage
Indian Institute of Technology Roorkee (IIT Roorkee) (Uttarakhand) uses the formula % = CGPA × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8.5 on the 10-point scale. Applying the official Indian Institute of Technology Roorkee (IIT Roorkee) formula % = CGPA × 10 gives a percentage of about 85%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
IIT Roorkee Notification No. Acd./6687/Senate-101 (13 July 2024), per Senate's 101st meeting (29.05.2024), Item 101.9
IIT Roorkee's 2024 Senate notification sets the conversion (notional) as CGPA × 10 (CGPA 8.5 → 85%), and treats a CGPA of 6.0 or above as First Division for employment/recruitment. This latest rule is plain ×10 — some third-party calculators wrongly cite ×9.5.
Comparing colleges? See the full CGPA to percentage directory or calculate your CGPA first with the CGPA calculator.