Indian Institute of Technology Roorkee (IIT Roorkee)
CGPA to percentage

Quick answer: At Indian Institute of Technology Roorkee (IIT Roorkee), a CGPA of 8.5 is about 85%, using the official formula % = CGPA × 10. (official source) Last verified 2026-07-19.

Indian Institute of Technology Roorkee (IIT Roorkee) — CGPA → %

CGPA (out of 10)

→

Percentage

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Formula: % = CGPA × 10Source: IIT Roorkee Notification No. Acd./6687/Senate-101 (13 July 2024), per Senate's 101st meeting (29.05.2024), Item 101.9Status: verifiedLast verified: 2026-07-19

Always confirm against your official grade card / university circular before using for applications.

How Indian Institute of Technology Roorkee (IIT Roorkee) converts CGPA to percentage

Indian Institute of Technology Roorkee (IIT Roorkee) (Uttarakhand) uses the formula % = CGPA × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.

Worked example

Take a CGPA of 8.5 on the 10-point scale. Applying the official Indian Institute of Technology Roorkee (IIT Roorkee) formula % = CGPA × 10 gives a percentage of about 85%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula — no rounding shortcuts.

Why the formula matters

Indian Institute of Technology Roorkee (IIT Roorkee) uses % = CGPA × 10 on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.

About Indian Institute of Technology Roorkee (IIT Roorkee)

The Indian Institute of Technology Roorkee (IIT Roorkee) is one of Asia's oldest technical institutions, founded in 1847 as the College of Civil Engineering at Roorkee, Uttarakhand, and converted into an IIT in 2001. An Institute of National Importance, it offers B.Tech, B.Arch, M.Tech, M.Sc, MBA and Ph.D programmes across engineering, sciences, architecture and management, and follows a 10-point credit-based grading system.

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Source & verification

IIT Roorkee's 2024 Senate notification sets the conversion (notional) as CGPA × 10 (CGPA 8.5 → 85%), and treats a CGPA of 6.0 or above as First Division for employment/recruitment. This latest rule is plain ×10 — some third-party calculators wrongly cite ×9.5.

Comparing universities? See the full CGPA to percentage directory or calculate your CGPA first with the CGPA calculator.

Frequently asked questions

What percentage is 8.5 CGPA at Indian Institute of Technology Roorkee (IIT Roorkee)?

Using the official formula % = CGPA × 10, a 8.5 CGPA is about 85% at Indian Institute of Technology Roorkee (IIT Roorkee). Enter any CGPA in the calculator above for an instant result.

Does Indian Institute of Technology Roorkee (IIT Roorkee) use CGPA × 10?

Yes — Indian Institute of Technology Roorkee (IIT Roorkee)'s official conversion is % = CGPA × 10.

Is this Indian Institute of Technology Roorkee (IIT Roorkee) conversion official?

The formula here is recorded from Indian Institute of Technology Roorkee (IIT Roorkee)'s published source and shown above with its verification status and the date last checked. Your transcript remains the authoritative document — this tool reproduces the university's own method.

Indian Institute of Technology Roorkee (IIT Roorkee)CGPA to percentage