Jawaharlal Nehru Government Engineering College (JNGEC), Sundernagar
CGPA to percentage
Quick answer: At Jawaharlal Nehru Government Engineering College (JNGEC), Sundernagar, a CGPA of 8 is about 76%, using the official formula % = CGPA × 9.5 (HPTU rule). (official source)
Jawaharlal Nehru Government Engineering College (JNGEC), Sundernagar — CGPA → %
How Jawaharlal Nehru Government Engineering College (JNGEC), Sundernagar converts CGPA to percentage
Jawaharlal Nehru Government Engineering College (JNGEC), Sundernagar (Himachal Pradesh) uses the formula % = CGPA × 9.5 (HPTU rule) to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8 on the 10-point scale. Applying the official Jawaharlal Nehru Government Engineering College (JNGEC), Sundernagar formula % = CGPA × 9.5 (HPTU rule) gives a percentage of about 76%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
INHERITED from Himachal Pradesh Technical University (registry key hptu): HPTU B.Tech Ordinance (OR-12): 'To convert CGPA into equivalent marks a multiplication factor of 9.5 is adopted'. Affiliation, from the college home page: an AICTE-approved, State Government funded engineering college affiliated to Himachal Pradesh Technical University (HimTU), Hamirpur.
State-government engineering college, not autonomous, affiliated to HPTU, so HPTU's ×9.5 applies. It is NOT ×10: CGPA 8.0 → 76%. The college publishes no conversion text of its own.
College contact
Address: JNGEC, Sundernagar, Mandi, Himachal Pradesh – 175018
Email: jngechp@yahoo.co.in
Phone: +91-1907-267688
Website: official contact page
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