J.P. Institute of Technology, Nalanda (SBTE Bihar)
CGPA to percentage
Quick answer: At J.P. Institute of Technology, Nalanda (SBTE Bihar), a CGPA of 8.75 is about 80%, using the official formula % = (CGPA − 0.75) × 10. (official source)
J.P. Institute of Technology, Nalanda (SBTE Bihar) — CGPA → %
How J.P. Institute of Technology, Nalanda (SBTE Bihar) converts CGPA to percentage
J.P. Institute of Technology, Nalanda (SBTE Bihar) (Bihar) uses the formula % = (CGPA − 0.75) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8.75 on the 10-point scale. Applying the official J.P. Institute of Technology, Nalanda (SBTE Bihar) formula % = (CGPA − 0.75) × 10 gives a percentage of about 80%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
State Board of Technical Education, Bihar (SBTE Patna) — CGPA to equivalent percentage conversion table (Letter No. 2734-SBTE, 18-07-2024)
J.P. Institute of Technology follows the State Board of Technical Education (SBTE) Bihar conversion table. The formula % = (CGPA − 0.75) × 10 matches the SBTE table exactly across the 5.25–9.75 CGPA range (e.g. 8.75 = 80%, 9.75 = 90%); the official SBTE table is authoritative near the extremes (it maps 5.00 → 40% and 10 → 95%).
College contact
Address: J.P. Institute of Technology, At.- Biyabani, P.O.- Maghra, Biharsharif, Dist. Nalanda, Bihar 803216, India.
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