Malla Reddy College of Engineering and Technology (MRCET)
CGPA to percentage
Quick answer: At Malla Reddy College of Engineering and Technology (MRCET), a CGPA of 8 is about 75%, using the official formula % = (CGPA − 0.5) × 10. (official source) Last verified 2026-07-20.
Malla Reddy College of Engineering and Technology (MRCET) — CGPA → %
How Malla Reddy College of Engineering and Technology (MRCET) converts CGPA to percentage
Malla Reddy College of Engineering and Technology (MRCET) (Telangana) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8 on the 10-point scale. Applying the official Malla Reddy College of Engineering and Technology (MRCET) formula % = (CGPA − 0.5) × 10 gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Malla Reddy College of Engineering and Technology (MRCET) is autonomous and sets its own conversion, % = (CGPA − 0.5) × 10, on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
MRCET B.Tech R20/R18 Academic Regulations, Section 12.0 (Declaration of results): “% of Marks = (final CGPA – 0.5) x 10”
Formula confirmed identically in MRCET's own R18 and R20 B.Tech regulations (Section 12.0). DISAMBIGUATION: MRCET on mrcet.com — distinct from other Malla Reddy institutions (MRCE, MREC, MRECW, Malla Reddy University, Malla Reddy Vishwavidyapeeth).
College contact
Address: Maisammaguda, Dhulapally, Secunderabad – 500100, Telangana, India
Email: mrcet2004@gmail.com
Phone: +91-9133555162
Website: official contact page
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