Pranveer Singh Institute of Technology (PSIT), Kanpur
CGPA to percentage
Quick answer: At Pranveer Singh Institute of Technology (PSIT), Kanpur, a CGPA of 8 is about 80%, using the official formula % = CGPA × 10 (inherited from AKTU — batches admitted before 2025-26). (official source)
Pranveer Singh Institute of Technology (PSIT), Kanpur — CGPA → %
How Pranveer Singh Institute of Technology (PSIT), Kanpur converts CGPA to percentage
Pranveer Singh Institute of Technology (PSIT), Kanpur (Uttar Pradesh) uses the formula % = CGPA × 10 (inherited from AKTU — batches admitted before 2025-26) to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8 on the 10-point scale. Applying the official Pranveer Singh Institute of Technology (PSIT), Kanpur formula % = CGPA × 10 (inherited from AKTU — batches admitted before 2025-26) gives a percentage of about 80%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Pranveer Singh Institute of Technology (PSIT), Kanpur is autonomous and sets its own conversion, % = CGPA × 10 (inherited from AKTU — batches admitted before 2025-26), on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
INHERITED from Dr. A.P.J. Abdul Kalam Technical University (registry key aktu): B.Tech ordinance effective 2018-19 (Revised), cl. 15: 'Conversion formula for the conversion of CGPA into Percentage is (CGPA ) x 10 = Percentage of marks scored.' PSIT's own engineering page links this AKTU ordinance.
Pre-autonomy batches keep AKTU's rule.
College contact
Address: Pranveer Singh Institute of Technology, National Highway (NH-19), Bhauti, Kanpur, Uttar Pradesh – 209305
Email: info@psit.ac.in
Phone: +91-512-2696244
Website: official contact page
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