Pandit Sundarlal Sharma (Open) University Chhattisgarh (PSSOU), Bilaspur
CGPA to percentage
Quick answer: At Pandit Sundarlal Sharma (Open) University Chhattisgarh (PSSOU), Bilaspur, a CGPA of 7.69 is about 76.9%, using the official formula % = CGPA × 10 (NEP FYUP, ODL mode). (official source)
Pandit Sundarlal Sharma (Open) University Chhattisgarh (PSSOU), Bilaspur — CGPA → %
How Pandit Sundarlal Sharma (Open) University Chhattisgarh (PSSOU), Bilaspur converts CGPA to percentage
Pandit Sundarlal Sharma (Open) University Chhattisgarh (PSSOU), Bilaspur (Chhattisgarh) uses the formula % = CGPA × 10 (NEP FYUP, ODL mode) to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 7.69 on the 10-point scale. Applying the official Pandit Sundarlal Sharma (Open) University Chhattisgarh (PSSOU), Bilaspur formula % = CGPA × 10 (NEP FYUP, ODL mode) gives a percentage of about 76.9%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Pandit Sundarlal Sharma (Open) University Chhattisgarh (PSSOU), Bilaspur is autonomous and sets its own conversion, % = CGPA × 10 (NEP FYUP, ODL mode), on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
Pandit Sundarlal Sharma (Open) University Chhattisgarh, Ordinance No. 1, E-1.1: Four Year Undergraduate Programme (FYUP), approved by the Karya Parishad meeting no. 20/Niyamit/2024 dated 28-05-2024, Section 11 'Conversion to Percentage': 'The conversion formula for converting the CGPA to the corresponding percentage (P) of marks will be as follows: P=10xCGPA'. Appendix-IV worked example: CGPA 7.69 → P = 10 × 7.69 = 76.9%.
Read in PSSOU's own compiled ordinance file, posted under 'HEI Compliance' (Dec 2024). It is the university's own copy of the Chhattisgarh uniform FYUP ordinance, adapted for open learning. Grade table (Appendix-III): >90–100 = O (10), >80–90 = A+ (9) … 40 = P (4), <40 = F.
College contact
Address: Pandit Sundarlal Sharma (Open) University, Koni-Birkona Road, Bilaspur, Chhattisgarh
Email: registrar@pssou.ac.in
Phone: +91-7752-298309
Website: official contact page
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