B.N.M. Institute of Technology (Autonomous), Banashankari, Bengaluru
percentage to CGPA
Quick answer: At B.N.M. Institute of Technology (Autonomous), Banashankari, Bengaluru, 72.5% is about a CGPA of 8 on the 10-point scale, reversing the official formula % = (CGPA − 0.75) × 10. (official source) Last verified 2026-08-17.
B.N.M. Institute of Technology (Autonomous), Banashankari, Bengaluru — % → CGPA
How to reverse B.N.M. Institute of Technology (Autonomous), Banashankari, Bengaluru's CGPA formula
B.N.M. Institute of Technology (Autonomous), Banashankari, Bengaluru (Karnataka) converts CGPA to percentage using % = (CGPA − 0.75) × 10. This page inverts that formula so you can estimate the CGPA behind a given percentage.
Worked example
Take a percentage of 72.5%. Reversing the official B.N.M. Institute of Technology (Autonomous), Banashankari, Bengaluru formula % = (CGPA − 0.75) × 10 gives a CGPA of about 8 on the 10-point scale. Change the percentage in the calculator above and the CGPA updates instantly.
Source & verification
B.N.M. Institute of Technology, Academic and Exam Rules and Regulations Applicable to all Autonomous UG/PG Programmes, clause 13.3.4 ‘Award of Class’: “The percentage of marks for a given SGPA/CGPA can be computed using the formula: % MARKS SCORED = [CGPA - 0.75] x 10.”
College contact
Address: B.N.M. Institute of Technology, Post Box No. 7087, 12th Main Road, 27th Cross, Banashankari II Stage, Bengaluru – 560 070, Karnataka, India
Email: bnmitprincipal@gmail.com
Phone: 080-26711781 / 26711782
Website: www.bnmit.org
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