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Kerala

College of Engineering Trivandrum (CET) (Autonomous)
percentage to CGPA

Quick answer: At College of Engineering Trivandrum (CET) (Autonomous), 80.0% is about a CGPA of 8, reversing the formula % = CGPA × 10. Last checked 2026-08-21.

College of Engineering Trivandrum (CET) (Autonomous) — % → CGPA

Formula: % = CGPA × 10Source: ‘B.Tech Academic Regulations, KTU 2024 Scheme’, hosted on CET's own site.Status: verifiedLast checked: 2026-08-21
Always confirm against your official grade card / college circular before using for applications.

How to reverse College of Engineering Trivandrum (CET) (Autonomous)'s CGPA formula

College of Engineering Trivandrum (CET) (Autonomous) (Kerala) converts CGPA to percentage using % = CGPA × 10. This page inverts that formula.

Worked example

Take a percentage of 80.0%. Reversing the College of Engineering Trivandrum (CET) (Autonomous) formula % = CGPA × 10 gives a CGPA of about 8.

Source & verification

‘B.Tech Academic Regulations, KTU 2024 Scheme’, hosted on CET's own site.

College contact

Address: College of Engineering Trivandrum, Engineering College P.O., Sreekaryam, Thiruvananthapuram - 695016, Kerala, India
Email: principal@cet.ac.in
Phone: 0471-2598370 / 0471-2998310
Website: www.cet.ac.in

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