M.V.J. College of Engineering (Autonomous), Bengaluru
percentage to CGPA
Quick answer: At M.V.J. College of Engineering (Autonomous), Bengaluru, 75.0% is about a CGPA of 8.25 on the 10-point scale, reversing the official formula % = (CGPA − 0.75) × 10. (official source) Last verified 2026-08-17.
M.V.J. College of Engineering (Autonomous), Bengaluru — % → CGPA
How to reverse M.V.J. College of Engineering (Autonomous), Bengaluru's CGPA formula
M.V.J. College of Engineering (Autonomous), Bengaluru (Karnataka) converts CGPA to percentage using % = (CGPA − 0.75) × 10. This page inverts that formula so you can estimate the CGPA behind a given percentage.
Worked example
Take a percentage of 75.0%. Reversing the official M.V.J. College of Engineering (Autonomous), Bengaluru formula % = (CGPA − 0.75) × 10 gives a CGPA of about 8.25 on the 10-point scale. Change the percentage in the calculator above and the CGPA updates instantly.
Source & verification
MVJCE Rules and Regulations (Undergraduate, Autonomous), clause 16.1 ‘Percentage equivalence of the Grade Points’: “Conversion formula for the Conversion of CGPA into Percentage on a 10-point Scale is given as Percentage of Marks Secured, P = [CGPA Earned - 0.75] × 10.”
College contact
Address: MVJ College of Engineering, Near ITPB, Whitefield, Bengaluru – 560 067, Karnataka, India
Email: helpdesk@mvjce.edu.in
Phone: 080-42991000
Website: www.mvjce.edu.in
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