SJB Institute of Technology (Autonomous), Bengaluru
percentage to CGPA
Quick answer: At SJB Institute of Technology (Autonomous), Bengaluru, 72.5% is about a CGPA of 8 on the 10-point scale, reversing the official formula % = (CGPA − 0.75) × 10. (official source) Last verified 2026-08-17.
SJB Institute of Technology (Autonomous), Bengaluru — % → CGPA
How to reverse SJB Institute of Technology (Autonomous), Bengaluru's CGPA formula
SJB Institute of Technology (Autonomous), Bengaluru (Karnataka) converts CGPA to percentage using % = (CGPA − 0.75) × 10. This page inverts that formula so you can estimate the CGPA behind a given percentage.
Worked example
Take a percentage of 72.5%. Reversing the official SJB Institute of Technology (Autonomous), Bengaluru formula % = (CGPA − 0.75) × 10 gives a CGPA of about 8 on the 10-point scale. Change the percentage in the calculator above and the CGPA updates instantly.
Source & verification
SJBIT, quoted institutional wording: “The Conversion formula for conversion of CGPA into percentage is as below: Percentage of Marks Secured, P = (CGPA earned − 0.75) × 10.” The full Autonomous Academic UG Regulations-2023 PDF is a scanned document without an extractable text layer.
College contact
Address: SJB Institute of Technology, BGS Health & Education City, Dr. Vishnuvardhan Road, Kengeri, Bengaluru – 560 060, Karnataka, India
Email: principal@sjbit.edu.in
Phone: 080-28612445 / 46
Website: www.sjbit.edu.in
Comparing colleges? See the full CGPA to percentage directory.