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Anurag Engineering College (Autonomous), Suryapet
CGPA to percentage

Anurag Engineering College (Autonomous), Suryapet — CGPA → %

Formula: % = (CGPA − 0.5) × 10Source: Anurag Engineering College (Autonomous), Ananthagiri, Suryapet — B.Tech Academic Regulations R18 (batches admitted from 2018-19), §18.11: 'The CGPA can be converted to equivalent percentage of marks by using the following equation: (CGPA − 0.5) × 10'Status: verifiedLast verified: 2026-06-23 · Anurag Engineering College, Suryapet states the conversion directly in its R18 regulations: equivalent percentage = (CGPA − 0.5) × 10 (CGPA 8.0 → 75%). This subtracts 0.5 before multiplying by 10, and is consistent with the institute's award-of-class thresholds (Distinction at CGPA 8.0 = 75%, First Class at 6.5 = 60%, Second Class at 5.5 = 50%, Pass at 5.0 = 45%). It uses a ten-point absolute grading scale: O = 10 (≥90%), A+ = 9 (80–90%), A = 8 (70–80%), B+ = 7 (60–70%), B = 6 (50–60%), P = 5 (40–50%, minimum pass), F = 0; a minimum CGPA of 5.0 is required for the degree. This is the autonomous college at Ananthagiri, Suryapet — a separate institution from Anurag Group of Institutions, Ghatkesar (Hyderabad), which uses the same formula.
Always confirm against your official grade card / university circular before using for applications.

How Anurag Engineering College (Autonomous), Suryapet converts CGPA to percentage

Anurag Engineering College (Autonomous), Suryapet (Telangana) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.

How CGPA is calculated at Anurag Engineering College (Autonomous), Suryapet

Your CGPA is a credit-weighted average of your grade points across all semesters. In short:

  1. Compute your CGPA on the college's ten-point grading scale (credit-weighted average of grade points across all courses).
  2. Subtract 0.5 from the CGPA, then multiply the result by 10 to get the equivalent percentage (R18 Regulations §18.11).
  3. Example: a CGPA of 8.0 gives (8.0 − 0.5) × 10 = 75%.
  4. Reverse: divide the percentage by 10 and add 0.5 to recover the CGPA.
  5. First Class corresponds to CGPA 6.5 (60%) and Distinction to CGPA 8.0 (75%).

Worked example. Applying % = (CGPA − 0.5) × 10, a CGPA of 8.0 converts to 75%.

About Anurag Engineering College (Autonomous), Suryapet

Anurag Engineering College (Autonomous) is an autonomous engineering college at Ananthagiri (V&M), Suryapet District, Telangana, affiliated to Jawaharlal Nehru Technological University Hyderabad (JNTUH). It offers undergraduate and postgraduate engineering programmes on a ten-point credit-and-grading system under its own Academic Council.

Address: Ananthagiri (V & M), Suryapet District – 508206, Telangana, India.

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Frequently asked questions

What percentage is 8 CGPA at Anurag Engineering College (Autonomous), Suryapet?
Using the official formula % = (CGPA − 0.5) × 10, a 8 CGPA is about 75% at Anurag Engineering College (Autonomous), Suryapet. Enter any CGPA in the calculator above for an instant result.
Does Anurag Engineering College (Autonomous), Suryapet use CGPA × 10?
Anurag Engineering College (Autonomous), Suryapet's official conversion is % = (CGPA − 0.5) × 10. So no — a plain ×10 would give the wrong number for this university.
Is this Anurag Engineering College (Autonomous), Suryapet conversion official?
The formula here is recorded from Anurag Engineering College (Autonomous), Suryapet's published source and shown above with its verification status and the date last checked. Your transcript remains the authoritative document — this tool reproduces the university's own method.