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Telangana

Anurag Engineering College (Autonomous), Suryapet
CGPA to percentage

Quick answer: At Anurag Engineering College (Autonomous), Suryapet, a CGPA of 8 is about 75%, using the official formula % = (CGPA − 0.5) × 10. (official source) Last verified 2026-07-19.

Anurag Engineering College (Autonomous), Suryapet — CGPA → %

Formula: % = (CGPA − 0.5) × 10Source: Anurag Engineering College (Autonomous), Ananthagiri, Suryapet — B.Tech Academic Regulations R18 (batches admitted from 2018-19), §18.11: 'The CGPA can be converted to equivalent percentage of marks by using the following equation: (CGPA − 0.5) × 10'Status: verifiedLast verified: 2026-07-19
Always confirm against your official grade card / university circular before using for applications.

How Anurag Engineering College (Autonomous), Suryapet converts CGPA to percentage

Anurag Engineering College (Autonomous), Suryapet (Telangana) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.

Worked example

Take a CGPA of 8 on the 10-point scale. Applying the official Anurag Engineering College (Autonomous), Suryapet formula % = (CGPA − 0.5) × 10 gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula — no rounding shortcuts.

Why the formula matters

It's tempting to assume CGPA × 10 everywhere, but that's only right for some universities. Anurag Engineering College (Autonomous), Suryapet uses % = (CGPA − 0.5) × 10, so a generic multiplier would give a different — and wrong — number on your application. Using the official conversion is what keeps your percentage defensible if an admissions office or employer asks how you calculated it.

About Anurag Engineering College (Autonomous), Suryapet

Anurag Engineering College (Autonomous) is an autonomous engineering college at Ananthagiri (V&M), Suryapet District, Telangana, affiliated to Jawaharlal Nehru Technological University Hyderabad (JNTUH). It offers undergraduate and postgraduate engineering programmes on a ten-point credit-and-grading system under its own Academic Council.

Address: Ananthagiri (V & M), Suryapet District – 508206, Telangana, India.

Source & verification

Anurag Engineering College, Suryapet states the conversion directly in its R18 regulations: equivalent percentage = (CGPA − 0.5) × 10 (CGPA 8.0 → 75%). This subtracts 0.5 before multiplying by 10, and is consistent with the institute's award-of-class thresholds (Distinction at CGPA 8.0 = 75%, First Class at 6.5 = 60%, Second Class at 5.5 = 50%, Pass at 5.0 = 45%). It uses a ten-point absolute grading scale: O = 10 (≥90%), A+ = 9 (80–90%), A = 8 (70–80%), B+ = 7 (60–70%), B = 6 (50–60%), P = 5 (40–50%, minimum pass), F = 0; a minimum CGPA of 5.0 is required for the degree. This is the autonomous college at Ananthagiri, Suryapet — a separate institution from Anurag Group of Institutions, Ghatkesar (Hyderabad), which uses the same formula.

Comparing universities? See the full CGPA to percentage directory or calculate your CGPA first with the CGPA calculator.

Frequently asked questions

What percentage is 8 CGPA at Anurag Engineering College (Autonomous), Suryapet?
Using the official formula % = (CGPA − 0.5) × 10, a 8 CGPA is about 75% at Anurag Engineering College (Autonomous), Suryapet. Enter any CGPA in the calculator above for an instant result.
Does Anurag Engineering College (Autonomous), Suryapet use CGPA × 10?
Anurag Engineering College (Autonomous), Suryapet's official conversion is % = (CGPA − 0.5) × 10. So no — a plain ×10 would give the wrong number for this university.
Is this Anurag Engineering College (Autonomous), Suryapet conversion official?
The formula here is recorded from Anurag Engineering College (Autonomous), Suryapet's published source and shown above with its verification status and the date last checked. Your transcript remains the authoritative document — this tool reproduces the university's own method.