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Telangana

Anurag Group of Institutions (Autonomous), Hyderabad
CGPA to percentage

Anurag Group of Institutions (Autonomous), Hyderabad — CGPA → %

Formula: % = (CGPA − 0.5) × 10Source: Anurag Group of Institutions (Autonomous) — B.Tech Academic Regulations R18 (batches admitted from 2018-19), §18 (Award of Class): 'The CGPA can be converted to equivalent percentage of marks by using the following equation: (CGPA − 0.5) × 10'Status: verifiedLast verified: 2026-06-23 · Anurag Group of Institutions states the conversion directly in its R18 regulations: equivalent percentage = (CGPA − 0.5) × 10 (CGPA 8.0 → 75%). This subtracts 0.5 before multiplying by 10, and is consistent with the institute's award-of-class thresholds (Distinction at CGPA 8.0 = 75%, First Class at 6.5 = 60%, Second Class at 5.5 = 50%, Pass at 5.0 = 45%). It uses a ten-point absolute grading scale: O = 10 (≥90%), A+ = 9 (80–90%), A = 8 (70–80%), B+ = 7 (60–70%), B = 6 (50–60%), C = 5 (40–50%, minimum pass), F = 0; a minimum CGPA of 5.0 is required for the degree. As an autonomous engineering college, this is set in its own Academic Council regulations.
Always confirm against your official grade card / university circular before using for applications.

How Anurag Group of Institutions (Autonomous), Hyderabad converts CGPA to percentage

Anurag Group of Institutions (Autonomous), Hyderabad (Telangana) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.

How CGPA is calculated at Anurag Group of Institutions (Autonomous), Hyderabad

Your CGPA is a credit-weighted average of your grade points across all semesters. In short:

  1. Compute your CGPA on the institute's ten-point grading scale (credit-weighted average of grade points across all courses).
  2. Subtract 0.5 from the CGPA, then multiply the result by 10 to get the equivalent percentage (R18 Regulations §18).
  3. Example: a CGPA of 8.0 gives (8.0 − 0.5) × 10 = 75%.
  4. Reverse: divide the percentage by 10 and add 0.5 to recover the CGPA.
  5. First Class corresponds to CGPA 6.5 (60%) and Distinction to CGPA 8.0 (75%).

Worked example. Applying % = (CGPA − 0.5) × 10, a CGPA of 8.0 converts to 75%.

About Anurag Group of Institutions (Autonomous), Hyderabad

Anurag Group of Institutions (Autonomous), formerly CVSR College of Engineering, is an autonomous engineering college at Venkatapur, Ghatkesar, near Hyderabad, Telangana, affiliated to Jawaharlal Nehru Technological University Hyderabad (JNTUH). It offers undergraduate and postgraduate engineering programmes on a ten-point credit-and-grading system under its own Academic Council. (It is associated with, but distinct from, Anurag University at the same location.)

Address: Venkatapur, Ghatkesar, Medchal–Malkajgiri District, Hyderabad – 500088, Telangana, India.

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Frequently asked questions

What percentage is 8 CGPA at Anurag Group of Institutions (Autonomous), Hyderabad?
Using the official formula % = (CGPA − 0.5) × 10, a 8 CGPA is about 75% at Anurag Group of Institutions (Autonomous), Hyderabad. Enter any CGPA in the calculator above for an instant result.
Does Anurag Group of Institutions (Autonomous), Hyderabad use CGPA × 10?
Anurag Group of Institutions (Autonomous), Hyderabad's official conversion is % = (CGPA − 0.5) × 10. So no — a plain ×10 would give the wrong number for this university.
Is this Anurag Group of Institutions (Autonomous), Hyderabad conversion official?
The formula here is recorded from Anurag Group of Institutions (Autonomous), Hyderabad's published source and shown above with its verification status and the date last checked. Your transcript remains the authoritative document — this tool reproduces the university's own method.