Central Institute of Technology Kokrajhar (CIT Kokrajhar), Kokrajhar
CGPA to percentage
Quick answer: At Central Institute of Technology Kokrajhar (CIT Kokrajhar), Kokrajhar, a CGPA of 8 is about 75%, using the official formula Piecewise (official): CGPA ≥ 9.0 → % = 15 × CGPA − 50; CGPA < 9.0 → % = 10 × CGPA − 5. (official source)
Central Institute of Technology Kokrajhar (CIT Kokrajhar), Kokrajhar — CGPA → %
How Central Institute of Technology Kokrajhar (CIT Kokrajhar), Kokrajhar converts CGPA to percentage
Central Institute of Technology Kokrajhar (CIT Kokrajhar), Kokrajhar (Assam) uses the formula Piecewise (official): CGPA ≥ 9.0 → % = 15 × CGPA − 50; CGPA < 9.0 → % = 10 × CGPA − 5 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8 on the 10-point scale. Applying the official Central Institute of Technology Kokrajhar (CIT Kokrajhar), Kokrajhar formula Piecewise (official): CGPA ≥ 9.0 → % = 15 × CGPA − 50; CGPA < 9.0 → % = 10 × CGPA − 5 gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Central Institute of Technology Kokrajhar (CIT Kokrajhar), Kokrajhar is autonomous and sets its own conversion, Piecewise (official): CGPA ≥ 9.0 → % = 15 × CGPA − 50; CGPA < 9.0 → % = 10 × CGPA − 5, on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
Central Institute of Technology Kokrajhar (Deemed to be University) — Ordinance (Diploma, UG, PG & PhD Programmes), April 2020, Section 7.7: 'For SGPA / CGPA ≥ 9.0, the equivalent % of Marks = 15 × CGPA – 50; For SGPA / CGPA < 9.0, the equivalent % of Marks = 10 × GPA – 5.0'. Same formula in the March 2019 Ordinance, clause 7.6; the PG and Diploma regulations (RA-1, RA-3) refer to OA clause 7.
Two-part (piecewise) formula: below CGPA 9.0, % = 10 × CGPA − 5 (so 8.0 → 75%, 6.0 → 55%); from 9.0 upward, % = 15 × CGPA − 50 (9.0 → 85%, 9.5 → 92.5%, 10 → 100%). The two parts meet at 9.0 = 85%, so the curve is continuous. The ordinance literally writes '10 × GPA – 5.0' in the second line — read as SGPA/CGPA as the sentence heading says. The OA cover page has unfilled approval blanks ('Amended and approved in the ….. Meeting of …'), but the PG and Diploma regulations (approved by Senate 2019/2020) cross-refer to OA clause 7 for equivalent percentage, and the 2019 version carries the same formula, so it is the operative rule. Applies to Diploma students as well as degree students.
College contact
Address: Central Institute of Technology Kokrajhar, PO: Rangalikhata/Balagaon, District: Kokrajhar (BTAD), Assam – 783370, India
Email: webmaster@cit.ac.in
Phone: +91-3661-277279
Website: official contact page
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