Government Autonomous College, Rourkela
CGPA to percentage
Quick answer: At Government Autonomous College, Rourkela, a CGPA of 8 is about 75%, using the official formula % = (CGPA − 0.5) × 10. (official source) Last verified 2026-07-21.
Government Autonomous College, Rourkela — CGPA → %
How Government Autonomous College, Rourkela converts CGPA to percentage
Government Autonomous College, Rourkela (Odisha) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8 on the 10-point scale. Applying the official Government Autonomous College, Rourkela formula % = (CGPA − 0.5) × 10 gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Government Autonomous College, Rourkela is autonomous and sets its own conversion, % = (CGPA − 0.5) × 10, on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
Government Autonomous College, Rourkela — official CGPA-to-Percentage conversion notice: “Percentage = (CGPA − 0.5) × 10”
Formula from the college's own official CGPA-to-Percentage notice: Percentage = (CGPA − 0.5) × 10, manually verified. The notice PDF is a scanned image (not machine-readable), so the value is per the user's manual reading; contact details are from official disclosure.
College contact
Address: At/Po Panposh, Rourkela – 769004, Sundargarh District, Odisha, India
Email: principalgacr@gmail.com
Phone: 0661-2664586
Website: official contact page
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