Ispat Autonomous College, Rourkela
CGPA to percentage
Quick answer: At Ispat Autonomous College, Rourkela, a CGPA of 8 is about 75.0%, using the formula % ≈ (CGPA − 0.5) × 10. Last checked 2026-08-21.
Ispat Autonomous College, Rourkela — CGPA → %
How Ispat Autonomous College, Rourkela converts CGPA to percentage
Ispat Autonomous College, Rourkela (Odisha) uses the formula % ≈ (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8. Applying the Ispat Autonomous College, Rourkela formula % ≈ (CGPA − 0.5) × 10 gives a percentage of about 75.0%.
Source & verification
Sambalpur University's own CBCS Regulation states ‘Percentage of Marks = (CGPA − 0.5) × 10’ with the O/E/A/B/C/D/P/F grade sequence — the same regulation independently confirmed at D.A.V. College Titilagarh (Sambalpur-affiliated); not independently confirmed as Ispat Autonomous College's own document specifically.
College contact
Address: Ved Vihar, Sector-16, Rourkela, Odisha - 769003, India
Email: ispatcoll@rediffmail.com
Phone: 0661-2646060
Website: ispatcollegerkl.com
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