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Home / CGPA to % / Indira Gandhi Institute of Technology (IGIT), Sarang
Odisha

Indira Gandhi Institute of Technology (IGIT), Sarang
CGPA to percentage

Quick answer: At Indira Gandhi Institute of Technology (IGIT), Sarang, a CGPA of 8 is about 75.0%, using the formula % = (CGPA − 0.5) × 10. Last checked 2026-08-21.

Indira Gandhi Institute of Technology (IGIT), Sarang — CGPA → %

Formula: % = (CGPA − 0.5) × 10Source: The college's own ‘academic regulations for m.tech/m.sc./mca (2 years)’.Status: verifiedLast checked: 2026-08-21
Always confirm against your official grade card / college circular before using for applications.

How Indira Gandhi Institute of Technology (IGIT), Sarang converts CGPA to percentage

Indira Gandhi Institute of Technology (IGIT), Sarang (Odisha) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage. Enter your CGPA above to convert it instantly.

Worked example

Take a CGPA of 8. Applying the Indira Gandhi Institute of Technology (IGIT), Sarang formula % = (CGPA − 0.5) × 10 gives a percentage of about 75.0%.

Source & verification

The college's own ‘academic regulations for m.tech/m.sc./mca (2 years)’.

College contact

Address: Sarang, Dhenkanal - 759146, Odisha, India
Email: principal@igitsarang.ac.in / contact@igitsarang.ac.in
Phone: +91-67682-67003
Website: igitsarang.ac.in

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