Indira Gandhi Institute of Technology (IGIT), Sarang
percentage to CGPA
Quick answer: At Indira Gandhi Institute of Technology (IGIT), Sarang, 75.0% is about a CGPA of 8, reversing the formula % = (CGPA − 0.5) × 10. Last checked 2026-08-21.
Indira Gandhi Institute of Technology (IGIT), Sarang — % → CGPA
How to reverse Indira Gandhi Institute of Technology (IGIT), Sarang's CGPA formula
Indira Gandhi Institute of Technology (IGIT), Sarang (Odisha) converts CGPA to percentage using % = (CGPA − 0.5) × 10. This page inverts that formula.
Worked example
Take a percentage of 75.0%. Reversing the Indira Gandhi Institute of Technology (IGIT), Sarang formula % = (CGPA − 0.5) × 10 gives a CGPA of about 8.
Source & verification
The college's own ‘academic regulations for m.tech/m.sc./mca (2 years)’.
College contact
Address: Sarang, Dhenkanal - 759146, Odisha, India
Email: principal@igitsarang.ac.in / contact@igitsarang.ac.in
Phone: +91-67682-67003
Website: igitsarang.ac.in
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