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Jawaharlal Nehru Technological University Hyderabad (JNTUH)
CGPA to percentage

Quick answer: At Jawaharlal Nehru Technological University Hyderabad (JNTUH), a CGPA of 7 is about 65%, using the official formula % = (CGPA − 0.5) × 10. (official source) Last verified 2026-07-19.

Jawaharlal Nehru Technological University Hyderabad (JNTUH) — CGPA → %

How Jawaharlal Nehru Technological University Hyderabad (JNTUH) converts CGPA to percentage

Jawaharlal Nehru Technological University Hyderabad (JNTUH) (Telangana) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.

Worked example

Take a CGPA of 7 on the 10-point scale. Applying the official Jawaharlal Nehru Technological University Hyderabad (JNTUH) formula % = (CGPA − 0.5) × 10 gives a percentage of about 65%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula — no rounding shortcuts.

Why the formula matters

It's tempting to assume CGPA × 10 everywhere, but that's only right for some universities. Jawaharlal Nehru Technological University Hyderabad (JNTUH) uses % = (CGPA − 0.5) × 10, so a generic multiplier would give a different — and wrong — number on your application. Using the official conversion is what keeps your percentage defensible if an admissions office or employer asks how you calculated it.

About Jawaharlal Nehru Technological University Hyderabad (JNTUH)

Jawaharlal Nehru Technological University Hyderabad (JNTUH), established by State Act No. 30 of 2008 and headquartered at Kukatpally, Hyderabad, Telangana, is one of the successor universities of the original JNTU. It is a major affiliating technological university for engineering and pharmacy colleges across Telangana, running its four-year B.Tech programme under the Choice Based Credit System on a ten-point absolute grading scale.

Address: Jawaharlal Nehru Technological University Hyderabad, Kukatpally, Hyderabad – 500085, Telangana, India.

Source & verification

JNTUH's B.Tech academic regulations convert the final CGPA to a percentage as % of Marks = (final CGPA − 0.5) × 10 (CGPA 7.0 → 65%). This same clause (§11.2) appears in both the R18 (2018-19 onwards) and R16 (2016-17 onwards) regulations. It is consistent with JNTUH's §12 award-of-class CGPA thresholds — First Class with Distinction ≥ 8.00, First Class ≥ 6.50 (= 60%), Second Class ≥ 5.50 (= 50%), Pass Class ≥ 5.00 — and the absolute 10-point grade table (O ≥ 90 = 10, A+ 80–90 = 9, A 70–80 = 8, B+ 60–70 = 7, B 50–60 = 6, C 40–50 = 5, F < 40 = 0). IMPORTANT: JNTUH uses a −0.5 offset, which is DIFFERENT from its sibling JNTU Kakinada (JNTUK), whose regulations use (CGPA − 0.75) × 10. The two differ by 2.5 percentage points at every CGPA, so the correct university must be used. JNTU Anantapur (JNTUA) publishes its own regulations and should be checked separately.

Comparing universities? See the full CGPA to percentage directory or calculate your CGPA first with the CGPA calculator.

Frequently asked questions

What percentage is 7 CGPA at Jawaharlal Nehru Technological University Hyderabad (JNTUH)?
Using the official formula % = (CGPA − 0.5) × 10, a 7 CGPA is about 65% at Jawaharlal Nehru Technological University Hyderabad (JNTUH). Enter any CGPA in the calculator above for an instant result.
Does Jawaharlal Nehru Technological University Hyderabad (JNTUH) use CGPA × 10?
Jawaharlal Nehru Technological University Hyderabad (JNTUH)'s official conversion is % = (CGPA − 0.5) × 10. So no — a plain ×10 would give the wrong number for this university.
Is this Jawaharlal Nehru Technological University Hyderabad (JNTUH) conversion official?
The formula here is recorded from Jawaharlal Nehru Technological University Hyderabad (JNTUH)'s published source and shown above with its verification status and the date last checked. Your transcript remains the authoritative document — this tool reproduces the university's own method.