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Home / % to CGPA / Jawaharlal Nehru Technological University Hyderabad (JNTUH)
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Jawaharlal Nehru Technological University Hyderabad (JNTUH)
percentage to CGPA

Jawaharlal Nehru Technological University Hyderabad (JNTUH) — % → CGPA

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Forward formula: % = (CGPA − 0.5) × 10Source: Jawaharlal Nehru Technological University Hyderabad — B.Tech Academic Regulations R18 (w.e.f. AY 2018-19), §11.2: '% of Marks = (final CGPA − 0.5) × 10'; identical clause in Academic Regulations R16 (w.e.f. AY 2016-17), §11.2; read with §12 award-of-class CGPA thresholdsStatus: verified
This reverses the official CGPA→% formula. A percentage on a transcript is the authoritative figure; the back-calculated CGPA is an estimate. Always confirm with your college.

Converting Jawaharlal Nehru Technological University Hyderabad (JNTUH) percentage back to CGPA

Jawaharlal Nehru Technological University Hyderabad (JNTUH) (Telangana) officially converts CGPA to percentage with % = (CGPA − 0.5) × 10. This page inverts that formula so you can estimate the CGPA behind a known percentage. Enter your percentage above and the calculator solves for the CGPA on the 10-point scale.

Worked example

The official Jawaharlal Nehru Technological University Hyderabad (JNTUH) formula is % = (CGPA − 0.5) × 10. Starting from a percentage of 65%, the formula reverses to a CGPA of about 7 on the 10-point scale. You can check this by running 7 through the forward Jawaharlal Nehru Technological University Hyderabad (JNTUH) CGPA to percentage calculator — it returns 65%, confirming the two directions agree.

Why this is an estimate, not an official figure

A college issues your percentage from your actual CGPA, not the other way around — so reversing the formula recovers the CGPA that would produce that percentage. When both numbers appear on your grade card, always quote the official CGPA rather than this estimate.

Source & verification

Jawaharlal Nehru Technological University Hyderabad — B.Tech Academic Regulations R18 (w.e.f. AY 2018-19), §11.2: '% of Marks = (final CGPA − 0.5) × 10'; identical clause in Academic Regulations R16 (w.e.f. AY 2016-17), §11.2; read with §12 award-of-class CGPA thresholds

JNTUH's B.Tech academic regulations convert the final CGPA to a percentage as % of Marks = (final CGPA − 0.5) × 10 (CGPA 7.0 → 65%). This same clause (§11.2) appears in both the R18 (2018-19 onwards) and R16 (2016-17 onwards) regulations. It is consistent with JNTUH's §12 award-of-class CGPA thresholds — First Class with Distinction ≥ 8.00, First Class ≥ 6.50 (= 60%), Second Class ≥ 5.50 (= 50%), Pass Class ≥ 5.00 — and the absolute 10-point grade table (O ≥ 90 = 10, A+ 80–90 = 9, A 70–80 = 8, B+ 60–70 = 7, B 50–60 = 6, C 40–50 = 5, F < 40 = 0). IMPORTANT: JNTUH uses a −0.5 offset, which is DIFFERENT from its sibling JNTU Kakinada (JNTUK), whose regulations use (CGPA − 0.75) × 10. The two differ by 2.5 percentage points at every CGPA, so the correct university must be used. JNTU Anantapur (JNTUA) publishes its own regulations and should be checked separately.

College contact

Address: Jawaharlal Nehru Technological University Hyderabad, Kukatpally, Hyderabad – 500085, Telangana, India.

Need the usual direction? Use the Jawaharlal Nehru Technological University Hyderabad (JNTUH) CGPA to percentage calculator, or browse the full percentage to CGPA directory.

Frequently asked questions

What CGPA is 65% at Jawaharlal Nehru Technological University Hyderabad (JNTUH)?
Reversing the official formula % = (CGPA − 0.5) × 10, 65% works out to roughly a 7 CGPA on the 10-point scale.
Is the reverse Jawaharlal Nehru Technological University Hyderabad (JNTUH) CGPA exact?
It's a close estimate. The college calculates your percentage from your CGPA, so reversing the formula recovers it accurately — but transcript rounding can introduce a small difference.