National Institute of Technology, Rourkela (NIT Rourkela)
CGPA to percentage
Quick answer: At National Institute of Technology, Rourkela (NIT Rourkela), a CGPA of 8.5 is about 85%, using the official formula % = CGPA × 10. (official source)
National Institute of Technology, Rourkela (NIT Rourkela) — CGPA → %
How National Institute of Technology, Rourkela (NIT Rourkela) converts CGPA to percentage
National Institute of Technology, Rourkela (NIT Rourkela) (Odisha) uses the formula % = CGPA × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8.5 on the 10-point scale. Applying the official National Institute of Technology, Rourkela (NIT Rourkela) formula % = CGPA × 10 gives a percentage of about 85%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
NIT Rourkela certificate No. NITR/AC/2021 (12-03-2021), per Senate Resolution Senate-98[2021]-12(7) dated 10-02-2021
NIT Rourkela states Equivalent Percentage = CGPA × 10, to be adopted notionally at the recipient's discretion. The institute follows a 7-point grade scale (Ex=10, A=9, B=8, C=7, D=6, P=5, F=2); the ×10 conversion is the officially notified rule regardless. Note on older records: an earlier NIT Rourkela conversion certificate used Percentage = 10 × CGPA − 5 (so e.g. CGPA 8.5 → 80% rather than 85%), and some older grade cards or third-party sources still cite that −5 form. It is superseded by the 2021 Senate-notified ×10 rule above.
Comparing colleges? See the full CGPA to percentage directory or calculate your CGPA first with the CGPA calculator.