Neelashaila Mahavidyalaya, Rourkela
CGPA to percentage
Quick answer: At Neelashaila Mahavidyalaya, Rourkela, a CGPA of 8 is about 75.0%, using the formula % ≈ (CGPA − 0.5) × 10. Last checked 2026-08-21.
Neelashaila Mahavidyalaya, Rourkela — CGPA → %
How Neelashaila Mahavidyalaya, Rourkela converts CGPA to percentage
Neelashaila Mahavidyalaya, Rourkela (Odisha) uses the formula % ≈ (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8. Applying the Neelashaila Mahavidyalaya, Rourkela formula % ≈ (CGPA − 0.5) × 10 gives a percentage of about 75.0%.
Source & verification
Sambalpur University's own CBCS Regulation states ‘Percentage of Marks = (CGPA − 0.5) × 10’ with the O/E/A/B/C/D/P/F grade sequence — the same regulation independently confirmed at D.A.V. College Titilagarh (Sambalpur-affiliated). Not independently confirmed as this specific college's own document.
College contact
Address: At-Niladrivihar, Jagda, Jhirpani, Rourkela, Sundargarh, Odisha - 769042, India
Email: nsm.rkl42@gmail.com
Phone: 0661-2476770 / 9238404443
Website: nsmvrkl.com (also referenced: nsmviqac.org.in, likely IQAC-specific)
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