Neelashaila Mahavidyalaya, Rourkela
percentage to CGPA
Quick answer: At Neelashaila Mahavidyalaya, Rourkela, 75.0% is about a CGPA of 8, reversing the formula % ≈ (CGPA − 0.5) × 10. Last checked 2026-08-21.
Neelashaila Mahavidyalaya, Rourkela — % → CGPA
How to reverse Neelashaila Mahavidyalaya, Rourkela's CGPA formula
Neelashaila Mahavidyalaya, Rourkela (Odisha) converts CGPA to percentage using % ≈ (CGPA − 0.5) × 10. This page inverts that formula.
Worked example
Take a percentage of 75.0%. Reversing the Neelashaila Mahavidyalaya, Rourkela formula % ≈ (CGPA − 0.5) × 10 gives a CGPA of about 8.
Source & verification
Sambalpur University's own CBCS Regulation states ‘Percentage of Marks = (CGPA − 0.5) × 10’ with the O/E/A/B/C/D/P/F grade sequence — the same regulation independently confirmed at D.A.V. College Titilagarh (Sambalpur-affiliated). Not independently confirmed as this specific college's own document.
College contact
Address: At-Niladrivihar, Jagda, Jhirpani, Rourkela, Sundargarh, Odisha - 769042, India
Email: nsm.rkl42@gmail.com
Phone: 0661-2476770 / 9238404443
Website: nsmvrkl.com (also referenced: nsmviqac.org.in, likely IQAC-specific)
Comparing colleges? See the full CGPA to percentage directory.