Veer Surendra Sai University of Technology (VSSUT), Burla
CGPA to percentage
Quick answer: At Veer Surendra Sai University of Technology (VSSUT), Burla, a CGPA of 8 is about 75%, using the official formula % = (CGPA − 0.5) × 10. (official source) Last verified 2026-07-19.
Veer Surendra Sai University of Technology (VSSUT), Burla — CGPA → %
How Veer Surendra Sai University of Technology (VSSUT), Burla converts CGPA to percentage
Veer Surendra Sai University of Technology (VSSUT), Burla (Odisha) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8 on the 10-point scale. Applying the official Veer Surendra Sai University of Technology (VSSUT), Burla formula % = (CGPA − 0.5) × 10 gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula — no rounding shortcuts.
Why the formula matters
It's tempting to assume CGPA × 10 everywhere, but that's only right for some universities. Veer Surendra Sai University of Technology (VSSUT), Burla uses % = (CGPA − 0.5) × 10, so a generic multiplier would give a different — and wrong — number on your application. Using the official conversion is what keeps your percentage defensible if an admissions office or employer asks how you calculated it.
About Veer Surendra Sai University of Technology (VSSUT), Burla
Veer Surendra Sai University of Technology (VSSUT), formerly University College of Engineering, Burla, is a public technological state university in Burla, Sambalpur district, Odisha. Established in 1956, it is the oldest engineering institution in Odisha and follows a 10-point credit-based grading system.
Address: Veer Surendra Sai University of Technology, Burla, Sambalpur – 768018, Odisha, India.
Source & verification
Formula STATED verbatim in VSSUT's own academic regulations (B.Tech 2016 read in full; identical wording also appears in the M.Tech wef-2016 and MCA regulations on vssut.ac.in): Percentage of marks = (CGPA − 0.5) × 10, printed on the final grade sheet. 10-point scale (A+=10, A=9, B+=8, B=7, C+=6, C=5, D=4, F=0). Degree award requires CGPA ≥ 6.0; promotion requires CGPA ≥ 5.5. DISAMBIGUATION: VSSUT Burla (Odisha state TECHNOLOGICAL university, the oldest engineering college in Odisha, est. 1956 as UCE Burla) is distinct from BPUT (Biju Patnaik University of Technology, the affiliating technical university, already covered separately) — VSSUT uses (CGPA − 0.5) × 10, and BPUT independently also uses (CGPA − 0.5) × 10, but they are different universities.
Comparing universities? See the full CGPA to percentage directory or calculate your CGPA first with the CGPA calculator.