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Home / CGPA to % / MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad
Telangana

MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad
CGPA to percentage

Quick answer: At MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad, a CGPA of 8 is about 75%, using the official formula % = (CGPA − 0.5) × 10. (official source)

MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad — CGPA → %

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Formula: % = (CGPA − 0.5) × 10Source: MLR Institute of Technology (Autonomous), Academic Regulations R25, B.Tech (batches admitted 2025-26; lateral entry 2026-27), Clause 19.1 'Conversion of CGPA into equivalent Percentage of Marks': 'The following formula shall be used for the conversion of CGPA into equivalent marks, whenever it is necessary' — 'Percentage (%) of Marks = (Final CGPA – 0.5) x 10'. The MLR18 (cl. 12.12) and MLR20 (cl. 14.12) regulations carry the same formula.Status: verifiedLast verified: 2026-10-09
Always confirm against your official grade card / college circular before using for applications.

How MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad converts CGPA to percentage

MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad (Telangana) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.

Worked example

Take a CGPA of 8 on the 10-point scale. Applying the official MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad formula % = (CGPA − 0.5) × 10 gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.

Why the formula matters

MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad is autonomous and sets its own conversion, % = (CGPA − 0.5) × 10, on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.

Source & verification

MLR Institute of Technology (Autonomous), Academic Regulations R25, B.Tech (batches admitted 2025-26; lateral entry 2026-27), Clause 19.1 'Conversion of CGPA into equivalent Percentage of Marks': 'The following formula shall be used for the conversion of CGPA into equivalent marks, whenever it is necessary' — 'Percentage (%) of Marks = (Final CGPA – 0.5) x 10'. The MLR18 (cl. 12.12) and MLR20 (cl. 14.12) regulations carry the same formula.

Explicit rule in the college's own autonomous regulations (same as JNTUH's).

College contact

Address: MLR Institute of Technology, Laxman Reddy Avenue, Survey No. 444, Dundigal, Hyderabad – 500043, Telangana
Email: director@mlrinstitutions.ac.in
Phone: +91-8418-204066
Website: official contact page

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Frequently asked questions

What percentage is 8 CGPA at MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad?
Using the official formula % = (CGPA − 0.5) × 10, a 8 CGPA is about 75% at MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad. Enter any CGPA in the calculator above for an instant result.
Which CGPA to percentage formula does MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad use?
MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad's official conversion is % = (CGPA − 0.5) × 10, taken from its own published source.
Is this MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad conversion official?
The formula here is recorded from MLR Institute of Technology (Autonomous) (MLRIT), Dundigal, Hyderabad's published source and shown above with its verification status and the date last checked. Your transcript remains the authoritative document — this tool reproduces the college's own method.

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