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Home / CGPA to % / SR Engineering College (Autonomous) (SREC), Warangal
Telangana

SR Engineering College (Autonomous) (SREC), Warangal
CGPA to percentage

Quick answer: At SR Engineering College (Autonomous) (SREC), Warangal, a CGPA of 8 is about 75%, using the official formula % = (CGPA − 0.5) × 10 (B.Tech RA15 / RA18). (official source)

SR Engineering College (Autonomous) (SREC), Warangal — CGPA → %

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Formula: % = (CGPA − 0.5) × 10 (B.Tech RA15 / RA18)Source: SR Engineering College (Autonomous), Warangal — 'Academic Regulations – RA18 for CBCS based Regular B.Tech. (UG) Program', cl. 11.2: 'For final percentage of marks equivalent to the computed final CGPA, the following formula may be used. % of marks = (final CGPA – 0.5) x 10'. The RA15 regulations (admitted 2015-16 onwards) carry the same clause 11.2.Status: verifiedLast verified: 2026-10-08
Always confirm against your official grade card / college circular before using for applications.

How SR Engineering College (Autonomous) (SREC), Warangal converts CGPA to percentage

SR Engineering College (Autonomous) (SREC), Warangal (Telangana) uses the formula % = (CGPA − 0.5) × 10 (B.Tech RA15 / RA18) to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.

Worked example

Take a CGPA of 8 on the 10-point scale. Applying the official SR Engineering College (Autonomous) (SREC), Warangal formula % = (CGPA − 0.5) × 10 (B.Tech RA15 / RA18) gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.

Why the formula matters

SR Engineering College (Autonomous) (SREC), Warangal is autonomous and sets its own conversion, % = (CGPA − 0.5) × 10 (B.Tech RA15 / RA18), on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.

Source & verification

SR Engineering College (Autonomous), Warangal — 'Academic Regulations – RA18 for CBCS based Regular B.Tech. (UG) Program', cl. 11.2: 'For final percentage of marks equivalent to the computed final CGPA, the following formula may be used. % of marks = (final CGPA – 0.5) x 10'. The RA15 regulations (admitted 2015-16 onwards) carry the same clause 11.2.

College-level rule, not SR University's. Not Sri Ramakrishna Engineering College, Coimbatore (srec).

College contact

Address: SR Engineering College, Ananthasagar (V), Hasanparthy (M), Warangal, Telangana – 506371
Email: ao@srecwarangal.ac.in
Phone: +91-870-2818333
Website: official contact page

Comparing colleges? See the full CGPA to percentage directory or calculate your CGPA first with the CGPA calculator.

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Frequently asked questions

What percentage is 8 CGPA at SR Engineering College (Autonomous) (SREC), Warangal?
Using the official formula % = (CGPA − 0.5) × 10 (B.Tech RA15 / RA18), a 8 CGPA is about 75% at SR Engineering College (Autonomous) (SREC), Warangal. Enter any CGPA in the calculator above for an instant result.
Which CGPA to percentage formula does SR Engineering College (Autonomous) (SREC), Warangal use?
SR Engineering College (Autonomous) (SREC), Warangal's official conversion is % = (CGPA − 0.5) × 10 (B.Tech RA15 / RA18), taken from its own published source.
Is this SR Engineering College (Autonomous) (SREC), Warangal conversion official?
The formula here is recorded from SR Engineering College (Autonomous) (SREC), Warangal's published source and shown above with its verification status and the date last checked. Your transcript remains the authoritative document — this tool reproduces the college's own method.

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