R.V.R. & J.C. College of Engineering (RVRJC)
CGPA to percentage
Quick answer: At R.V.R. & J.C. College of Engineering (RVRJC), a CGPA of 8 is about 75%, using the official formula % = (CGPA − 0.5) × 10. (official source) Last verified 2026-07-20.
R.V.R. & J.C. College of Engineering (RVRJC) — CGPA → %
How R.V.R. & J.C. College of Engineering (RVRJC) converts CGPA to percentage
R.V.R. & J.C. College of Engineering (RVRJC) (Andhra Pradesh) uses the formula % = (CGPA − 0.5) × 10 to convert a 10-point CGPA into a percentage for transcripts, job applications and higher studies. Enter your CGPA above to convert it instantly.
Worked example
Take a CGPA of 8 on the 10-point scale. Applying the official R.V.R. & J.C. College of Engineering (RVRJC) formula % = (CGPA − 0.5) × 10 gives a percentage of about 75%. Change the CGPA in the calculator above and the percentage updates instantly using this same formula.
Why the formula matters
R.V.R. & J.C. College of Engineering (RVRJC) is autonomous and sets its own conversion, % = (CGPA − 0.5) × 10, on its 10-point scale. Using the official conversion keeps your percentage defensible if an admissions office or employer asks how you calculated it.
Source & verification
RVRJC B.Tech R24 Academic Regulations, Clause 18.9 (Grading): “Conversion of CGPA into equivalent Percentage : Percentage of Marks =(CGPA-0.50)x10”
Formula from RVRJC's own autonomous R24 B.Tech regulations (Clause 18.9). No general email is published on the current official website; only phone/address are listed.
College contact
Address: Chandramoulipuram, Chowdavaram, Guntur – 522019, Andhra Pradesh, India
Phone: 0863-2232505
Website: official contact page
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